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11331123101233 = 13871624853941
BaseRepresentation
bin1010010011100011101110…
…0100010011111000110001
31111010020121110012001200121
42210320323210103320301
52441122120003214413
640033240204450241
72246434536124315
oct244707344237061
944106543161617
1011331123101233
113679558652881
12133006a249981
1364269c1c65a0
142b2601d55b45
15149b3638cb8d
hexa4e3b913e31

11331123101233 has 4 divisors (see below), whose sum is σ = 12202747955188. Its totient is φ = 10459498247280.

The previous prime is 11331123101203. The next prime is 11331123101257. The reversal of 11331123101233 is 33210132113311.

11331123101233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2182391653264 + 9148731447969 = 1477292^2 + 3024687^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331123101233 - 237 = 11193684147761 is a prime.

It is a super-2 number, since 2×113311231012332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11331123101198 and 11331123101207.

It is not an unprimeable number, because it can be changed into a prime (11331123101203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435812426958 + ... + 435812426983.

It is an arithmetic number, because the mean of its divisors is an integer number (3050686988797).

Almost surely, 211331123101233 is an apocalyptic number.

11331123101233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11331123101233 is a deficient number, since it is larger than the sum of its proper divisors (871624853955).

11331123101233 is an equidigital number, since it uses as much as digits as its factorization.

11331123101233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 871624853954.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11331123101233 its reverse (33210132113311), we get a palindrome (44541255214544).

The spelling of 11331123101233 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-three million, one hundred one thousand, two hundred thirty-three".

Divisors: 1 13 871624853941 11331123101233