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11331123112147 is a prime number
BaseRepresentation
bin1010010011100011101110…
…0100010110100011010011
31111010020121110012121122211
42210320323210112203103
52441122120004042042
640033240205012551
72246434536201166
oct244707344264323
944106543177584
1011331123112147
11367955865aaa3
12133006a254157
1364269c1cb547
142b2601d59add
15149b36391017
hexa4e3b9168d3

11331123112147 has 2 divisors, whose sum is σ = 11331123112148. Its totient is φ = 11331123112146.

The previous prime is 11331123112087. The next prime is 11331123112151. The reversal of 11331123112147 is 74121132113311.

11331123112147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11331123112147 - 27 = 11331123112019 is a prime.

It is not a weakly prime, because it can be changed into another prime (11331123110147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665561556073 + 5665561556074.

It is an arithmetic number, because the mean of its divisors is an integer number (5665561556074).

Almost surely, 211331123112147 is an apocalyptic number.

11331123112147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331123112147 is an equidigital number, since it uses as much as digits as its factorization.

11331123112147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3024, while the sum is 31.

Adding to 11331123112147 its reverse (74121132113311), we get a palindrome (85452255225458).

The spelling of 11331123112147 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-three million, one hundred twelve thousand, one hundred forty-seven".