Base | Representation |
---|---|
bin | 1010010011100011101110… |
… | …0101001011110011001011 |
3 | 1111010020121110121200211202 |
4 | 2210320323211023303023 |
5 | 2441122120033032001 |
6 | 40033240213414415 |
7 | 2246434541100104 |
oct | 244707345136313 |
9 | 44106543550752 |
10 | 11331123330251 |
11 | 367955879994a |
12 | 133006a33a40b |
13 | 64269c2768ba |
14 | 2b2601db53ab |
15 | 149b363d596b |
hex | a4e3b94bccb |
11331123330251 has 2 divisors, whose sum is σ = 11331123330252. Its totient is φ = 11331123330250.
The previous prime is 11331123330169. The next prime is 11331123330269. The reversal of 11331123330251 is 15203332113311.
It is a strong prime.
It is an emirp because it is prime and its reverse (15203332113311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11331123330251 is a prime.
It is a super-3 number, since 3×113311233302513 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11331123333251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665561665125 + 5665561665126.
It is an arithmetic number, because the mean of its divisors is an integer number (5665561665126).
Almost surely, 211331123330251 is an apocalyptic number.
11331123330251 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331123330251 is an equidigital number, since it uses as much as digits as its factorization.
11331123330251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 29.
Adding to 11331123330251 its reverse (15203332113311), we get a palindrome (26534455443562).
The spelling of 11331123330251 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-three million, three hundred thirty thousand, two hundred fifty-one".
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