113311245341035 has 48 divisors (see below), whose sum is σ = 159316929518400. Its totient is φ = 77137953177600.

The previous prime is 113311245340981. The next prime is 113311245341057. The reversal of 113311245341035 is 530143542113311.

It is a de Polignac number, because none of the positive numbers 2^k-113311245341035 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113311245340985 and 113311245341003.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 60376491 + ... + 62224939.

It is an arithmetic number, because the mean of its divisors is an integer number (3319102698300).

Almost surely, 2^{113311245341035} is an apocalyptic number.

113311245341035 is a deficient number, since it is larger than the sum of its proper divisors (46005684177365).

113311245341035 is a wasteful number, since it uses less digits than its factorization.

113311245341035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1850276 (or 1850269 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 37.

Adding to 113311245341035 its reverse (530143542113311), we get a palindrome (643454787454346).

The spelling of 113311245341035 in words is "one hundred thirteen trillion, three hundred eleven billion, two hundred forty-five million, three hundred forty-one thousand, thirty-five".