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113311245340981 is a prime number
BaseRepresentation
bin11001110000111001010100…
…100001110001000100110101
3112212012110010111211121002201
4121300321110201301010311
5104322442412301402411
61040554244551104501
732603316201521062
oct3160712441610465
9485173114747081
10113311245340981
1133117035a822a6
121086058a972131
134b2c28762847c
141dda417671c69
15d177439b83c1
hex670e54871135

113311245340981 has 2 divisors, whose sum is σ = 113311245340982. Its totient is φ = 113311245340980.

The previous prime is 113311245340963. The next prime is 113311245341057. The reversal of 113311245340981 is 189043542113311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108243028728081 + 5068216612900 = 10403991^2 + 2251270^2 .

It is a cyclic number.

It is not a de Polignac number, because 113311245340981 - 217 = 113311245209909 is a prime.

It is a super-2 number, since 2×1133112453409812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113311245340781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655622670490 + 56655622670491.

It is an arithmetic number, because the mean of its divisors is an integer number (56655622670491).

Almost surely, 2113311245340981 is an apocalyptic number.

It is an amenable number.

113311245340981 is a deficient number, since it is larger than the sum of its proper divisors (1).

113311245340981 is an equidigital number, since it uses as much as digits as its factorization.

113311245340981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 46.

The spelling of 113311245340981 in words is "one hundred thirteen trillion, three hundred eleven billion, two hundred forty-five million, three hundred forty thousand, nine hundred eighty-one".