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11331131233 is a prime number
BaseRepresentation
bin10101000110110001…
…10101011101100001
31002020200112002220011
422203120311131201
5141201232144413
65112213244521
7550540012012
oct124330653541
932220462804
1011331131233
114895145674
122242933741
1310b77052a6
14796c69009
15464b9c33d
hex2a3635761

11331131233 has 2 divisors, whose sum is σ = 11331131234. Its totient is φ = 11331131232.

The previous prime is 11331131167. The next prime is 11331131243. The reversal of 11331131233 is 33213113311.

11331131233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9850959504 + 1480171729 = 99252^2 + 38473^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331131233 - 29 = 11331130721 is a prime.

It is a super-5 number, since 5×113311312335 (a number of 51 digits) contains 55555 as substring.

It is not a weakly prime, because it can be changed into another prime (11331131243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565616 + 5665565617.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565617).

Almost surely, 211331131233 is an apocalyptic number.

It is an amenable number.

11331131233 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131233 is an equidigital number, since it uses as much as digits as its factorization.

11331131233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 486, while the sum is 22.

Adding to 11331131233 its reverse (33213113311), we get a palindrome (44544244544).

The spelling of 11331131233 in words is "eleven billion, three hundred thirty-one million, one hundred thirty-one thousand, two hundred thirty-three".