11331131311231 has 4 divisors (see below), whose sum is σ = 11823789194352. Its totient is φ = 10838473428112.

The previous prime is 11331131311229. The next prime is 11331131311237. The reversal of 11331131311231 is 13211313113311.

11331131311231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11331131311231 - 2¹ = 11331131311229 is a prime.

It is a super-3 number, since 3×11331131311231³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11331131311196 and 11331131311205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331131311237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 246328941526 + ... + 246328941571.

It is an arithmetic number, because the mean of its divisors is an integer number (2955947298588).

Almost surely, 2^{11331131311231} is an apocalyptic number.

11331131311231 is a deficient number, since it is larger than the sum of its proper divisors (492657883121).

11331131311231 is an equidigital number, since it uses as much as digits as its factorization.

11331131311231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 492657883120.

The product of its digits is 486, while the sum is 25.

Adding to 11331131311231 its reverse (13211313113311), we get a palindrome (24542444424542).

The spelling of 11331131311231 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred eleven thousand, two hundred thirty-one".