Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …1010011101110011100101 |
3 | 1111010020122011000012222202 |
4 | 2210320330022131303211 |
5 | 2441122130033301313 |
6 | 40033241203104245 |
7 | 2246435020133051 |
oct | 244707412356345 |
9 | 44106564005882 |
10 | 11331133103333 |
11 | 367956326457a |
12 | 1330071672085 |
13 | 6426a12b90a4 |
14 | 2b26033dac61 |
15 | 149b371b6558 |
hex | a4e3c29dce5 |
11331133103333 has 8 divisors (see below), whose sum is σ = 11448030353088. Its totient is φ = 11214237515904.
The previous prime is 11331133103327. The next prime is 11331133103369. The reversal of 11331133103333 is 33330133113311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11331133103333 - 240 = 10231621475557 is a prime.
It is a super-3 number, since 3×113311331033333 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11331133103296 and 11331133103305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331133103383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17056760 + ... + 17708622.
It is an arithmetic number, because the mean of its divisors is an integer number (1431003794136).
Almost surely, 211331133103333 is an apocalyptic number.
It is an amenable number.
11331133103333 is a deficient number, since it is larger than the sum of its proper divisors (116897249755).
11331133103333 is an equidigital number, since it uses as much as digits as its factorization.
11331133103333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 831163.
The product of its (nonzero) digits is 6561, while the sum is 29.
Adding to 11331133103333 its reverse (33330133113311), we get a palindrome (44661266216644).
The spelling of 11331133103333 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-three million, one hundred three thousand, three hundred thirty-three".
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