Base | Representation |
---|---|
bin | 10101000110110001… |
… | …10111101011100011 |
3 | 1002020200112120100211 |
4 | 22203120313223203 |
5 | 141201232442243 |
6 | 5112213354551 |
7 | 550540050346 |
oct | 124330675343 |
9 | 32220476324 |
10 | 11331140323 |
11 | 4895151488 |
12 | 2242938a57 |
13 | 10b7709479 |
14 | 796c6c45d |
15 | 464b9ed9d |
hex | 2a3637ae3 |
11331140323 has 2 divisors, whose sum is σ = 11331140324. Its totient is φ = 11331140322.
The previous prime is 11331140309. The next prime is 11331140341. The reversal of 11331140323 is 32304113311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331140323 - 217 = 11331009251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11331140294 and 11331140303.
It is not a weakly prime, because it can be changed into another prime (11331140123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665570161 + 5665570162.
It is an arithmetic number, because the mean of its divisors is an integer number (5665570162).
Almost surely, 211331140323 is an apocalyptic number.
11331140323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331140323 is an equidigital number, since it uses as much as digits as its factorization.
11331140323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 11331140323 its reverse (32304113311), we get a palindrome (43635253634).
The spelling of 11331140323 in words is "eleven billion, three hundred thirty-one million, one hundred forty thousand, three hundred twenty-three".
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