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113311431304003 = 4912887448117839
BaseRepresentation
bin11001110000111001011111…
…100111001010001101000011
3112212012110121110202111102001
4121300321133213022031003
5104322443302403212003
61040554315233004431
732603323620263242
oct3160713747121503
9485173543674361
10113311431304003
1133117120a48049
12108606210b3717
134b2c2b700956a
141dda43423c959
15d17754e9d61d
hex670e5f9ca343

113311431304003 has 16 divisors (see below), whose sum is σ = 113613252756480. Its totient is φ = 113009923353600.

The previous prime is 113311431303991. The next prime is 113311431304031. The reversal of 113311431304003 is 300403134113311.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 113311431304003 - 217 = 113311431172931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113311432304003) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6351884758 + ... + 6351902596.

It is an arithmetic number, because the mean of its divisors is an integer number (7100828297280).

Almost surely, 2113311431304003 is an apocalyptic number.

113311431304003 is a deficient number, since it is larger than the sum of its proper divisors (301821452477).

113311431304003 is a wasteful number, since it uses less digits than its factorization.

113311431304003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25698.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 113311431304003 its reverse (300403134113311), we get a palindrome (413714565417314).

The spelling of 113311431304003 in words is "one hundred thirteen trillion, three hundred eleven billion, four hundred thirty-one million, three hundred four thousand, three".

Divisors: 1 491 2887 4481 17839 1417517 2200171 8758949 12936647 51501193 79936559 6351893677 25287085763 39248850469 230776845833 113311431304003