Base | Representation |
---|---|
bin | 11001110000111001011111… |
… | …101010111110010110000011 |
3 | 112212012110121112122022011002 |
4 | 121300321133222332112003 |
5 | 104322443303132212003 |
6 | 1040554315310242215 |
7 | 32603323631626553 |
oct | 3160713752762603 |
9 | 485173545568132 |
10 | 113311432304003 |
11 | 3311712157039a |
12 | 108606214b636b |
13 | 4b2c2b729978b |
14 | 1dda43441d163 |
15 | d177550e9a88 |
hex | 670e5fabe583 |
113311432304003 has 2 divisors, whose sum is σ = 113311432304004. Its totient is φ = 113311432304002.
The previous prime is 113311432303943. The next prime is 113311432304017. The reversal of 113311432304003 is 300403234113311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113311432304003 - 212 = 113311432299907 is a prime.
It is not a weakly prime, because it can be changed into another prime (113311432304503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655716152001 + 56655716152002.
It is an arithmetic number, because the mean of its divisors is an integer number (56655716152002).
Almost surely, 2113311432304003 is an apocalyptic number.
113311432304003 is a deficient number, since it is larger than the sum of its proper divisors (1).
113311432304003 is an equidigital number, since it uses as much as digits as its factorization.
113311432304003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 113311432304003 its reverse (300403234113311), we get a palindrome (413714666417314).
The spelling of 113311432304003 in words is "one hundred thirteen trillion, three hundred eleven billion, four hundred thirty-two million, three hundred four thousand, three".
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