Base | Representation |
---|---|
bin | 1010010011100011111100… |
… | …1010111011010100101011 |
3 | 1111010020202122221110212201 |
4 | 2210320333022323110223 |
5 | 2441122230442242013 |
6 | 40033250204321031 |
7 | 2246436202024042 |
oct | 244707712732453 |
9 | 44106678843781 |
10 | 11331183555883 |
11 | 36795897942a4 |
12 | 1330086543177 |
13 | 6426ab8a2479 |
14 | 2b2609db1559 |
15 | 149b3b8303dd |
hex | a4e3f2bb52b |
11331183555883 has 2 divisors, whose sum is σ = 11331183555884. Its totient is φ = 11331183555882.
The previous prime is 11331183555787. The next prime is 11331183555893. The reversal of 11331183555883 is 38855538113311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331183555883 - 221 = 11331181458731 is a prime.
It is a super-2 number, since 2×113311835558832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11331183555893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665591777941 + 5665591777942.
It is an arithmetic number, because the mean of its divisors is an integer number (5665591777942).
Almost surely, 211331183555883 is an apocalyptic number.
11331183555883 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331183555883 is an equidigital number, since it uses as much as digits as its factorization.
11331183555883 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184000, while the sum is 55.
The spelling of 11331183555883 in words is "eleven trillion, three hundred thirty-one billion, one hundred eighty-three million, five hundred fifty-five thousand, eight hundred eighty-three".
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