Base | Representation |
---|---|
bin | 1010010011100100000000… |
… | …1010011011001000111001 |
3 | 1111010020210211021011001122 |
4 | 2210321000022123020321 |
5 | 2441122244222420043 |
6 | 40033252001155025 |
7 | 2246436463351631 |
oct | 244710012331071 |
9 | 44106724234048 |
10 | 11331200201273 |
11 | 3679598123217 |
12 | 133009002ba75 |
13 | 6426b217ca04 |
14 | 2b260c2a56c1 |
15 | 149b3d01c368 |
hex | a4e4029b239 |
11331200201273 has 2 divisors, whose sum is σ = 11331200201274. Its totient is φ = 11331200201272.
The previous prime is 11331200201231. The next prime is 11331200201317. The reversal of 11331200201273 is 37210200213311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6758736459049 + 4572463742224 = 2599757^2 + 2138332^2 .
It is an emirp because it is prime and its reverse (37210200213311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11331200201273 - 210 = 11331200200249 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331200201473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665600100636 + 5665600100637.
It is an arithmetic number, because the mean of its divisors is an integer number (5665600100637).
Almost surely, 211331200201273 is an apocalyptic number.
It is an amenable number.
11331200201273 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331200201273 is an equidigital number, since it uses as much as digits as its factorization.
11331200201273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 11331200201273 its reverse (37210200213311), we get a palindrome (48541400414584).
The spelling of 11331200201273 in words is "eleven trillion, three hundred thirty-one billion, two hundred million, two hundred one thousand, two hundred seventy-three".
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