Base | Representation |
---|---|
bin | 10101000110110010… |
… | …00110110011111001 |
3 | 1002020200122201101011 |
4 | 22203121012303321 |
5 | 141201241433142 |
6 | 5112214553521 |
7 | 550540426132 |
oct | 124331066371 |
9 | 32220581334 |
10 | 11331202297 |
11 | 4895193aa8 |
12 | 22429688a1 |
13 | 10b772b73c |
14 | 796c86c89 |
15 | 464bb3417 |
hex | 2a3646cf9 |
11331202297 has 2 divisors, whose sum is σ = 11331202298. Its totient is φ = 11331202296.
The previous prime is 11331202279. The next prime is 11331202301. The reversal of 11331202297 is 79220213311.
Together with previous prime (11331202279) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11304792976 + 26409321 = 106324^2 + 5139^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11331202297 is a prime.
It is a super-2 number, since 2×113312022972 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11331206297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665601148 + 5665601149.
It is an arithmetic number, because the mean of its divisors is an integer number (5665601149).
Almost surely, 211331202297 is an apocalyptic number.
It is an amenable number.
11331202297 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331202297 is an equidigital number, since it uses as much as digits as its factorization.
11331202297 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4536, while the sum is 31.
The spelling of 11331202297 in words is "eleven billion, three hundred thirty-one million, two hundred two thousand, two hundred ninety-seven".
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