Base | Representation |
---|---|
bin | 1010010011100100000101… |
… | …0110000010011110100011 |
3 | 1111010020212012120012122012 |
4 | 2210321001112002132203 |
5 | 2441122314311220303 |
6 | 40033253550103135 |
7 | 2246440124006543 |
oct | 244710126023643 |
9 | 44106765505565 |
10 | 11331220023203 |
11 | 36795a8331783 |
12 | 13300967aaaab |
13 | 6426b6300072 |
14 | 2b2610b85323 |
15 | 149b3eb355d8 |
hex | a4e415827a3 |
11331220023203 has 2 divisors, whose sum is σ = 11331220023204. Its totient is φ = 11331220023202.
The previous prime is 11331220023191. The next prime is 11331220023241. The reversal of 11331220023203 is 30232002213311.
It is a weak prime.
It is an emirp because it is prime and its reverse (30232002213311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11331220023203 - 24 = 11331220023187 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331720023203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665610011601 + 5665610011602.
It is an arithmetic number, because the mean of its divisors is an integer number (5665610011602).
Almost surely, 211331220023203 is an apocalyptic number.
11331220023203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331220023203 is an equidigital number, since it uses as much as digits as its factorization.
11331220023203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11331220023203 its reverse (30232002213311), we get a palindrome (41563222236514).
The spelling of 11331220023203 in words is "eleven trillion, three hundred thirty-one billion, two hundred twenty million, twenty-three thousand, two hundred three".
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