Base | Representation |
---|---|
bin | 10101000110110010… |
… | …01110100101000001 |
3 | 1002020200201100000112 |
4 | 22203121032211001 |
5 | 141201243442423 |
6 | 5112215401105 |
7 | 550540620653 |
oct | 124331164501 |
9 | 32220640015 |
10 | 11331234113 |
11 | 48952059a1 |
12 | 2242983195 |
13 | 10b7740074 |
14 | 796c946d3 |
15 | 464bbca78 |
hex | 2a364e941 |
11331234113 has 2 divisors, whose sum is σ = 11331234114. Its totient is φ = 11331234112.
The previous prime is 11331234091. The next prime is 11331234121. The reversal of 11331234113 is 31143213311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7410971569 + 3920262544 = 86087^2 + 62612^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331234113 - 218 = 11330971969 is a prime.
It is a super-2 number, since 2×113312341132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11331234133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665617056 + 5665617057.
It is an arithmetic number, because the mean of its divisors is an integer number (5665617057).
Almost surely, 211331234113 is an apocalyptic number.
It is an amenable number.
11331234113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331234113 is an equidigital number, since it uses as much as digits as its factorization.
11331234113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 648, while the sum is 23.
Adding to 11331234113 its reverse (31143213311), we get a palindrome (42474447424).
The spelling of 11331234113 in words is "eleven billion, three hundred thirty-one million, two hundred thirty-four thousand, one hundred thirteen".
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