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113313011153 is a prime number
BaseRepresentation
bin110100110000111111…
…0110101010111010001
3101211110222102101021212
41221201332311113101
53324031112324103
6124015535025505
711121000463046
oct1514176652721
9354428371255
10113313011153
1144068271461
1219b6436b295
13a8ba9b6534
1456ad1c91cd
152e32dba7d8
hex1a61fb55d1

113313011153 has 2 divisors, whose sum is σ = 113313011154. Its totient is φ = 113313011152.

The previous prime is 113313011137. The next prime is 113313011183. The reversal of 113313011153 is 351110313311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92445186304 + 20867824849 = 304048^2 + 144457^2 .

It is an emirp because it is prime and its reverse (351110313311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113313011153 - 24 = 113313011137 is a prime.

It is not a weakly prime, because it can be changed into another prime (113313011183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656505576 + 56656505577.

It is an arithmetic number, because the mean of its divisors is an integer number (56656505577).

Almost surely, 2113313011153 is an apocalyptic number.

It is an amenable number.

113313011153 is a deficient number, since it is larger than the sum of its proper divisors (1).

113313011153 is an equidigital number, since it uses as much as digits as its factorization.

113313011153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405, while the sum is 23.

Adding to 113313011153 its reverse (351110313311), we get a palindrome (464423324464).

The spelling of 113313011153 in words is "one hundred thirteen billion, three hundred thirteen million, eleven thousand, one hundred fifty-three".