11331320433 has 4 divisors (see below), whose sum is σ = 15108427248. Its totient is φ = 7554213620.

The previous prime is 11331320387. The next prime is 11331320459. The reversal of 11331320433 is 33402313311.

It is a happy number.

11331320433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11331320433 - 2⁸ = 11331320177 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11331321433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1888553403 + ... + 1888553408.

It is an arithmetic number, because the mean of its divisors is an integer number (3777106812).

Almost surely, 2^11331320433 is an apocalyptic number.

It is an amenable number.

11331320433 is a deficient number, since it is larger than the sum of its proper divisors (3777106815).

11331320433 is an equidigital number, since it uses as much as digits as its factorization.

11331320433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3777106814.

The product of its (nonzero) digits is 1944, while the sum is 24.

Adding to 11331320433 its reverse (33402313311), we get a palindrome (44733633744).

The spelling of 11331320433 in words is "eleven billion, three hundred thirty-one million, three hundred twenty thousand, four hundred thirty-three".