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113313210216937 is a prime number
BaseRepresentation
bin11001110000111011001001…
…101001001011000111101001
3112212012122012110002122012021
4121300323021221023013221
5104323010423303420222
61040555211541144441
732603415660633313
oct3160731151130751
9485178173078167
10113313210216937
1133117954109725
1210860a389bb121
134b2c50b725473
141dda5625c67b3
15d1780b23dac7
hex670ec9a4b1e9

113313210216937 has 2 divisors, whose sum is σ = 113313210216938. Its totient is φ = 113313210216936.

The previous prime is 113313210216881. The next prime is 113313210217003. The reversal of 113313210216937 is 739612012313311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113189576405481 + 123633811456 = 10639059^2 + 351616^2 .

It is a cyclic number.

It is not a de Polignac number, because 113313210216937 - 231 = 113311062733289 is a prime.

It is a super-4 number, since 4×1133132102169374 (a number of 57 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113313210216893 and 113313210216902.

It is not a weakly prime, because it can be changed into another prime (113313210211937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656605108468 + 56656605108469.

It is an arithmetic number, because the mean of its divisors is an integer number (56656605108469).

Almost surely, 2113313210216937 is an apocalyptic number.

It is an amenable number.

113313210216937 is a deficient number, since it is larger than the sum of its proper divisors (1).

113313210216937 is an equidigital number, since it uses as much as digits as its factorization.

113313210216937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 122472, while the sum is 43.

The spelling of 113313210216937 in words is "one hundred thirteen trillion, three hundred thirteen billion, two hundred ten million, two hundred sixteen thousand, nine hundred thirty-seven".