Base | Representation |
---|---|
bin | 1010010011100100011101… |
… | …0111010100101101101011 |
3 | 1111010021010020121112202222 |
4 | 2210321013113110231223 |
5 | 2441123021140221324 |
6 | 40033311554544255 |
7 | 2246442461335562 |
oct | 244710727245553 |
9 | 44107106545688 |
10 | 11331321023339 |
11 | 367964a346669 |
12 | 133010459808b |
13 | 642701203b65 |
14 | 2b2620356bd9 |
15 | 149b4893655e |
hex | a4e475d4b6b |
11331321023339 has 2 divisors, whose sum is σ = 11331321023340. Its totient is φ = 11331321023338.
The previous prime is 11331321023203. The next prime is 11331321023371. The reversal of 11331321023339 is 93332012313311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331321023339 - 224 = 11331304246123 is a prime.
It is a super-2 number, since 2×113313210233392 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11331321023299 and 11331321023308.
It is not a weakly prime, because it can be changed into another prime (11331321029339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665660511669 + 5665660511670.
It is an arithmetic number, because the mean of its divisors is an integer number (5665660511670).
Almost surely, 211331321023339 is an apocalyptic number.
11331321023339 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331321023339 is an equidigital number, since it uses as much as digits as its factorization.
11331321023339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 35.
The spelling of 11331321023339 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty-one million, twenty-three thousand, three hundred thirty-nine".
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