Base | Representation |
---|---|
bin | 1010010011100100011111… |
… | …1010011000000000011011 |
3 | 1111010021010212220101001211 |
4 | 2210321013322120000123 |
5 | 2441123031013234432 |
6 | 40033312523523551 |
7 | 2246442632415361 |
oct | 244710772300033 |
9 | 44107125811054 |
10 | 11331330211867 |
11 | 3679654552096 |
12 | 13301076895b7 |
13 | 6427030a0263 |
14 | 2b2621669631 |
15 | 149b4964dd47 |
hex | a4e47e9801b |
11331330211867 has 2 divisors, whose sum is σ = 11331330211868. Its totient is φ = 11331330211866.
The previous prime is 11331330211801. The next prime is 11331330211889. The reversal of 11331330211867 is 76811203313311.
It is a strong prime.
It is an emirp because it is prime and its reverse (76811203313311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11331330211867 - 211 = 11331330209819 is a prime.
It is a super-2 number, since 2×113313302118672 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11331330221867) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665665105933 + 5665665105934.
It is an arithmetic number, because the mean of its divisors is an integer number (5665665105934).
Almost surely, 211331330211867 is an apocalyptic number.
11331330211867 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331330211867 is an equidigital number, since it uses as much as digits as its factorization.
11331330211867 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 40.
The spelling of 11331330211867 in words is "eleven trillion, three hundred thirty-one billion, three hundred thirty million, two hundred eleven thousand, eight hundred sixty-seven".
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