Base | Representation |
---|---|
bin | 11001110000111100010001… |
… | …001110111100110100001000 |
3 | 112212012202022011011002100212 |
4 | 121300330101032330310020 |
5 | 104323020403243132102 |
6 | 1040555531044420252 |
7 | 32603460513661424 |
oct | 3160742116746410 |
9 | 485182264132325 |
10 | 113314411302152 |
11 | 33118410096835 |
12 | 108611130a7688 |
13 | 4b2c670509888 |
14 | 1dda637d19b84 |
15 | d1787b8e0c52 |
hex | 670f113bcd08 |
113314411302152 has 32 divisors (see below), whose sum is σ = 221259084641280. Its totient is φ = 54344336551680.
The previous prime is 113314411302151. The next prime is 113314411302179. The reversal of 113314411302152 is 251203114413311.
It is a super-2 number, since 2×1133144113021522 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (113314411302151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2021710688 + ... + 2021766735.
It is an arithmetic number, because the mean of its divisors is an integer number (6914346395040).
Almost surely, 2113314411302152 is an apocalyptic number.
It is an amenable number.
113314411302152 is a deficient number, since it is larger than the sum of its proper divisors (107944673339128).
113314411302152 is a wasteful number, since it uses less digits than its factorization.
113314411302152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4043477573 (or 4043477569 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 113314411302152 its reverse (251203114413311), we get a palindrome (364517525715463).
The spelling of 113314411302152 in words is "one hundred thirteen trillion, three hundred fourteen billion, four hundred eleven million, three hundred two thousand, one hundred fifty-two".
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