Base | Representation |
---|---|
bin | 10000011111010111111… |
… | …111010101101101110111 |
3 | 11000022222122220210221202 |
4 | 100133113333111231313 |
5 | 122031243211314221 |
6 | 2224330203003115 |
7 | 144604516646402 |
oct | 20372777255567 |
9 | 4008878823852 |
10 | 1133200104311 |
11 | 3a7650a09830 |
12 | 16375650949b |
13 | 82b25147502 |
14 | 3cbc0926d39 |
15 | 1e7254e8d0b |
hex | 107d7fd5b77 |
1133200104311 has 32 divisors (see below), whose sum is σ = 1261116311040. Its totient is φ = 1009548835200.
The previous prime is 1133200104287. The next prime is 1133200104341. The reversal of 1133200104311 is 1134010023311.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1133200104311 is a prime.
It is a super-2 number, since 2×11332001043112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1133200104341) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 327418121 + ... + 327421581.
It is an arithmetic number, because the mean of its divisors is an integer number (39409884720).
Almost surely, 21133200104311 is an apocalyptic number.
1133200104311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1133200104311 is a deficient number, since it is larger than the sum of its proper divisors (127916206729).
1133200104311 is a wasteful number, since it uses less digits than its factorization.
1133200104311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4967.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1133200104311 its reverse (1134010023311), we get a palindrome (2267210127622).
The spelling of 1133200104311 in words is "one trillion, one hundred thirty-three billion, two hundred million, one hundred four thousand, three hundred eleven".
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