11332003131133 has 4 divisors (see below), whose sum is σ = 11437909702560. Its totient is φ = 11226096559708.

The previous prime is 11332003131121. The next prime is 11332003131157. The reversal of 11332003131133 is 33113130023311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11332003131133 - 2⁵ = 11332003131101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11332003131098 and 11332003131107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11332003131173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52953285553 + ... + 52953285766.

It is an arithmetic number, because the mean of its divisors is an integer number (2859477425640).

Almost surely, 2^{11332003131133} is an apocalyptic number.

It is an amenable number.

11332003131133 is a deficient number, since it is larger than the sum of its proper divisors (105906571427).

11332003131133 is a wasteful number, since it uses less digits than its factorization.

11332003131133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105906571426.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 11332003131133 its reverse (33113130023311), we get a palindrome (44445133154444).

The spelling of 11332003131133 in words is "eleven trillion, three hundred thirty-two billion, three million, one hundred thirty-one thousand, one hundred thirty-three".