Base | Representation |
---|---|
bin | 1010010011100111000010… |
… | …0011101100101100010001 |
3 | 1111010022220102001120012011 |
4 | 2210321300203230230101 |
5 | 2441130430101230022 |
6 | 40033504323502521 |
7 | 2246465552562133 |
oct | 244716043545421 |
9 | 44108812046164 |
10 | 11332012133137 |
11 | 3679974473693 |
12 | 1330277b27a41 |
13 | 6427b144c877 |
14 | 2b2688059053 |
15 | 149b8944e977 |
hex | a4e708ecb11 |
11332012133137 has 2 divisors, whose sum is σ = 11332012133138. Its totient is φ = 11332012133136.
The previous prime is 11332012133081. The next prime is 11332012133179. The reversal of 11332012133137 is 73133121023311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6583103851536 + 4748908281601 = 2565756^2 + 2179199^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11332012133137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11332012133099 and 11332012133108.
It is not a weakly prime, because it can be changed into another prime (11332012131137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666006066568 + 5666006066569.
It is an arithmetic number, because the mean of its divisors is an integer number (5666006066569).
Almost surely, 211332012133137 is an apocalyptic number.
It is an amenable number.
11332012133137 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332012133137 is an equidigital number, since it uses as much as digits as its factorization.
11332012133137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 31.
Adding to 11332012133137 its reverse (73133121023311), we get a palindrome (84465133156448).
The spelling of 11332012133137 in words is "eleven trillion, three hundred thirty-two billion, twelve million, one hundred thirty-three thousand, one hundred thirty-seven".
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