Base | Representation |
---|---|
bin | 1010010011100111000111… |
… | …0011011010011101010011 |
3 | 1111010022221212101020020222 |
4 | 2210321301303122131103 |
5 | 2441131000423424341 |
6 | 40033510351423255 |
7 | 2246466225314633 |
oct | 244716163323523 |
9 | 44108855336228 |
10 | 11332033029971 |
11 | 36799852467a5 |
12 | 1330282b24b2b |
13 | 6427b5888264 |
14 | 2b268ab386c3 |
15 | 149b8b1cb44b |
hex | a4e71cda753 |
11332033029971 has 2 divisors, whose sum is σ = 11332033029972. Its totient is φ = 11332033029970.
The previous prime is 11332033029943. The next prime is 11332033030099. The reversal of 11332033029971 is 17992033023311.
It is a weak prime.
It is an emirp because it is prime and its reverse (17992033023311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11332033029971 is a prime.
It is not a weakly prime, because it can be changed into another prime (11332036029971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666016514985 + 5666016514986.
It is an arithmetic number, because the mean of its divisors is an integer number (5666016514986).
Almost surely, 211332033029971 is an apocalyptic number.
11332033029971 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332033029971 is an equidigital number, since it uses as much as digits as its factorization.
11332033029971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 183708, while the sum is 44.
The spelling of 11332033029971 in words is "eleven trillion, three hundred thirty-two billion, thirty-three million, twenty-nine thousand, nine hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •