Base | Representation |
---|---|
bin | 10000011111011000001… |
… | …011100100110111111000 |
3 | 11000022222212221210020111 |
4 | 100133120023210313320 |
5 | 122031300021441440 |
6 | 2224330355434104 |
7 | 144604556136535 |
oct | 20373013446770 |
9 | 4008885853214 |
10 | 1133203312120 |
11 | 3a76527aa910 |
12 | 1637575b5934 |
13 | 82b259cb619 |
14 | 3cbc111dd8c |
15 | 1e72592e4ea |
hex | 107d82e4df8 |
1133203312120 has 256 divisors, whose sum is σ = 3075208934400. Its totient is φ = 370953461760.
The previous prime is 1133203312063. The next prime is 1133203312147. The reversal of 1133203312120 is 212133023311.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 1133203312091 and 1133203312100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 23186029 + ... + 23234851.
It is an arithmetic number, because the mean of its divisors is an integer number (12012534900).
Almost surely, 21133203312120 is an apocalyptic number.
1133203312120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1133203312120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1537604467200).
1133203312120 is an abundant number, since it is smaller than the sum of its proper divisors (1942005622280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1133203312120 is a wasteful number, since it uses less digits than its factorization.
1133203312120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48998 (or 48994 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1133203312120 its reverse (212133023311), we get a palindrome (1345336335431).
The spelling of 1133203312120 in words is "one trillion, one hundred thirty-three billion, two hundred three million, three hundred twelve thousand, one hundred twenty".
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