1133203312777 has 2 divisors, whose sum is σ = 1133203312778. Its totient is φ = 1133203312776.

The previous prime is 1133203312733. The next prime is 1133203312781. The reversal of 1133203312777 is 7772133023311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1133083607296 + 119705481 = 1064464^2 + 10941^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1133203312777 is a prime.

It is not a weakly prime, because it can be changed into another prime (1133203319777) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566601656388 + 566601656389.

It is an arithmetic number, because the mean of its divisors is an integer number (566601656389).

Almost surely, 2^{1133203312777} is an apocalyptic number.

It is an amenable number.

1133203312777 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133203312777 is an equidigital number, since it uses as much as digits as its factorization.

1133203312777 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 111132, while the sum is 40.

The spelling of 1133203312777 in words is "one trillion, one hundred thirty-three billion, two hundred three million, three hundred twelve thousand, seven hundred seventy-seven".