113330010113 has 2 divisors, whose sum is σ = 113330010114. Its totient is φ = 113330010112.

The previous prime is 113330010103. The next prime is 113330010169. The reversal of 113330010113 is 311010033311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 83438366449 + 29891643664 = 288857^2 + 172892^2 .

It is a cyclic number.

It is not a de Polignac number, because 113330010113 - 2¹⁴ = 113329993729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113330010091 and 113330010100.

It is not a weakly prime, because it can be changed into another prime (113330010103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56665005056 + 56665005057.

It is an arithmetic number, because the mean of its divisors is an integer number (56665005057).

Almost surely, 2^113330010113 is an apocalyptic number.

It is an amenable number.

113330010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113330010113 is an equidigital number, since it uses as much as digits as its factorization.

113330010113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 113330010113 its reverse (311010033311), we get a palindrome (424340043424).

The spelling of 113330010113 in words is "one hundred thirteen billion, three hundred thirty million, ten thousand, one hundred thirteen".