1133300241131 has 2 divisors, whose sum is σ = 1133300241132. Its totient is φ = 1133300241130.

The previous prime is 1133300241079. The next prime is 1133300241233. The reversal of 1133300241131 is 1311420033311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1133300241131 - 2³⁰ = 1132226499307 is a prime.

It is a super-2 number, since 2×1133300241131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1133300241097 and 1133300241106.

It is not a weakly prime, because it can be changed into another prime (1133300241431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566650120565 + 566650120566.

It is an arithmetic number, because the mean of its divisors is an integer number (566650120566).

Almost surely, 2^{1133300241131} is an apocalyptic number.

1133300241131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133300241131 is an equidigital number, since it uses as much as digits as its factorization.

1133300241131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1133300241131 its reverse (1311420033311), we get a palindrome (2444720274442).

The spelling of 1133300241131 in words is "one trillion, one hundred thirty-three billion, three hundred million, two hundred forty-one thousand, one hundred thirty-one".