11333012113 has 2 divisors, whose sum is σ = 11333012114. Its totient is φ = 11333012112.

The previous prime is 11333012069. The next prime is 11333012123. The reversal of 11333012113 is 31121033311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11072931984 + 260080129 = 105228^2 + 16127^2 .

It is an emirp because it is prime and its reverse (31121033311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11333012113 is a prime.

It is not a weakly prime, because it can be changed into another prime (11333012123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666506056 + 5666506057.

It is an arithmetic number, because the mean of its divisors is an integer number (5666506057).

Almost surely, 2^11333012113 is an apocalyptic number.

It is an amenable number.

11333012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11333012113 is an equidigital number, since it uses as much as digits as its factorization.

11333012113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11333012113 its reverse (31121033311), we get a palindrome (42454045424).

The spelling of 11333012113 in words is "eleven billion, three hundred thirty-three million, twelve thousand, one hundred thirteen".