Base | Representation |
---|---|
bin | 1010010011101010110010… |
… | …1001101101111110001011 |
3 | 1111010102111200011222202202 |
4 | 2210322230221231332023 |
5 | 2441140011202003303 |
6 | 40034152341150415 |
7 | 2246532544332035 |
oct | 244725451557613 |
9 | 44112450158682 |
10 | 11333020344203 |
11 | 367a341595578 |
12 | 13304b96bb40b |
13 | 6429122a326c |
14 | 2b2741d02c55 |
15 | 149be7c03c88 |
hex | a4eaca6df8b |
11333020344203 has 2 divisors, whose sum is σ = 11333020344204. Its totient is φ = 11333020344202.
The previous prime is 11333020344133. The next prime is 11333020344223. The reversal of 11333020344203 is 30244302033311.
It is a strong prime.
It is an emirp because it is prime and its reverse (30244302033311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11333020344203 - 210 = 11333020343179 is a prime.
It is not a weakly prime, because it can be changed into another prime (11333020344223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666510172101 + 5666510172102.
It is an arithmetic number, because the mean of its divisors is an integer number (5666510172102).
Almost surely, 211333020344203 is an apocalyptic number.
11333020344203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11333020344203 is an equidigital number, since it uses as much as digits as its factorization.
11333020344203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 11333020344203 its reverse (30244302033311), we get a palindrome (41577322377514).
The spelling of 11333020344203 in words is "eleven trillion, three hundred thirty-three billion, twenty million, three hundred forty-four thousand, two hundred three".
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