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113330300010131 is a prime number
BaseRepresentation
bin11001110001001011000100…
…010001100011111010010011
3112212021021022110120002012202
4121301023010101203322103
5104323300423300311011
61041011115430513415
732604562324526261
oct3161130421437223
9485237273502182
10113330300010131
1133124123928256
121086420820586b
134b310031c7629
141ddb30419b431
15d17eab75123b
hex6712c4463e93

113330300010131 has 2 divisors, whose sum is σ = 113330300010132. Its totient is φ = 113330300010130.

The previous prime is 113330300010101. The next prime is 113330300010163. The reversal of 113330300010131 is 131010003033311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113330300010131 - 214 = 113330299993747 is a prime.

It is a super-3 number, since 3×1133303000101313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (113330300010101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56665150005065 + 56665150005066.

It is an arithmetic number, because the mean of its divisors is an integer number (56665150005066).

Almost surely, 2113330300010131 is an apocalyptic number.

113330300010131 is a deficient number, since it is larger than the sum of its proper divisors (1).

113330300010131 is an equidigital number, since it uses as much as digits as its factorization.

113330300010131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 113330300010131 its reverse (131010003033311), we get a palindrome (244340303043442).

The spelling of 113330300010131 in words is "one hundred thirteen trillion, three hundred thirty billion, three hundred million, ten thousand, one hundred thirty-one".