11333121112133 has 4 divisors (see below), whose sum is σ = 11333130543168. Its totient is φ = 11333111681100.

The previous prime is 11333121112121. The next prime is 11333121112211. The reversal of 11333121112133 is 33121112133311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11333121112133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11333121112433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2595191 + ... + 5422292.

It is an arithmetic number, because the mean of its divisors is an integer number (2833282635792).

Almost surely, 2^{11333121112133} is an apocalyptic number.

It is an amenable number.

11333121112133 is a deficient number, since it is larger than the sum of its proper divisors (9431035).

11333121112133 is an equidigital number, since it uses as much as digits as its factorization.

11333121112133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9431034.

The product of its digits is 972, while the sum is 26.

Adding to 11333121112133 its reverse (33121112133311), we get a palindrome (44454233245444).

The spelling of 11333121112133 in words is "eleven trillion, three hundred thirty-three billion, one hundred twenty-one million, one hundred twelve thousand, one hundred thirty-three".