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11333121212993 is a prime number
BaseRepresentation
bin1010010011101011001010…
…1010100000001001000001
31111010102202200222122201212
42210322302222200021001
52441140213012303433
640034210343135505
72246535210603116
oct244726252401101
944112680878655
1011333121212993
11367a39351a808
121330527444595
1364292a15c338
142b275147c90d
15149c019cad48
hexa4eb2aa0241

11333121212993 has 2 divisors, whose sum is σ = 11333121212994. Its totient is φ = 11333121212992.

The previous prime is 11333121212957. The next prime is 11333121213019. The reversal of 11333121212993 is 39921212133311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10712221340209 + 620899872784 = 3272953^2 + 787972^2 .

It is a cyclic number.

It is not a de Polignac number, because 11333121212993 - 28 = 11333121212737 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11333121212993.

It is not a weakly prime, because it can be changed into another prime (11333121212953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666560606496 + 5666560606497.

It is an arithmetic number, because the mean of its divisors is an integer number (5666560606497).

Almost surely, 211333121212993 is an apocalyptic number.

It is an amenable number.

11333121212993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11333121212993 is an equidigital number, since it uses as much as digits as its factorization.

11333121212993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 52488, while the sum is 41.

The spelling of 11333121212993 in words is "eleven trillion, three hundred thirty-three billion, one hundred twenty-one million, two hundred twelve thousand, nine hundred ninety-three".