Base | Representation |
---|---|
bin | 10000011111011110101… |
… | …110110001001111101011 |
3 | 11000100021112201201121212 |
4 | 100133132232301033223 |
5 | 122032011134414011 |
6 | 2224345323023335 |
7 | 144610362156626 |
oct | 20373656611753 |
9 | 4010245651555 |
10 | 1133313201131 |
11 | 3a76a9836081 |
12 | 16378836ab4b |
13 | 82b426c52c7 |
14 | 3cbd1966dbd |
15 | 1e7303d908b |
hex | 107debb13eb |
1133313201131 has 2 divisors, whose sum is σ = 1133313201132. Its totient is φ = 1133313201130.
The previous prime is 1133313201103. The next prime is 1133313201143. The reversal of 1133313201131 is 1311023133311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1133313201131 is a prime.
It is a super-2 number, since 2×11333132011312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1133313201097 and 1133313201106.
It is not a weakly prime, because it can be changed into another prime (1133313201101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566656600565 + 566656600566.
It is an arithmetic number, because the mean of its divisors is an integer number (566656600566).
Almost surely, 21133313201131 is an apocalyptic number.
1133313201131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133313201131 is an equidigital number, since it uses as much as digits as its factorization.
1133313201131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 1133313201131 its reverse (1311023133311), we get a palindrome (2444336334442).
The spelling of 1133313201131 in words is "one trillion, one hundred thirty-three billion, three hundred thirteen million, two hundred one thousand, one hundred thirty-one".
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