Base | Representation |
---|---|
bin | 10000011111011110101… |
… | …111001001011001110011 |
3 | 11000100021112220202100202 |
4 | 100133132233021121303 |
5 | 122032011201100313 |
6 | 2224345325105415 |
7 | 144610363051256 |
oct | 20373657113163 |
9 | 4010245822322 |
10 | 1133313300083 |
11 | 3a76a98a3458 |
12 | 1637883b826b |
13 | 82b4272b363 |
14 | 3cbd199109d |
15 | 1e730408558 |
hex | 107debc9673 |
1133313300083 has 2 divisors, whose sum is σ = 1133313300084. Its totient is φ = 1133313300082.
The previous prime is 1133313299959. The next prime is 1133313300103. The reversal of 1133313300083 is 3800033133311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1133313300083 - 210 = 1133313299059 is a prime.
It is a super-2 number, since 2×11333133000832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1133313300283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566656650041 + 566656650042.
It is an arithmetic number, because the mean of its divisors is an integer number (566656650042).
Almost surely, 21133313300083 is an apocalyptic number.
1133313300083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133313300083 is an equidigital number, since it uses as much as digits as its factorization.
1133313300083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 1133313300083 its reverse (3800033133311), we get a palindrome (4933346433394).
The spelling of 1133313300083 in words is "one trillion, one hundred thirty-three billion, three hundred thirteen million, three hundred thousand, eighty-three".
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