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1133320232013 = 3377773410671
BaseRepresentation
bin10000011111011111001…
…001100101110001001101
311000100022000221221011220
4100133133021211301031
5122032014434411023
62224350133433553
7144610506012054
oct20373711456115
94010260857156
101133320232013
113a77027a8522
1216378a79b8b9
1382b43cb75a8
143cbd287739b
151e730d273e3
hex107df265c4d

1133320232013 has 4 divisors (see below), whose sum is σ = 1511093642688. Its totient is φ = 755546821340.

The previous prime is 1133320231987. The next prime is 1133320232021. The reversal of 1133320232013 is 3102320233311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1133320232013 - 225 = 1133286677581 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133320232713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188886705333 + ... + 188886705338.

It is an arithmetic number, because the mean of its divisors is an integer number (377773410672).

Almost surely, 21133320232013 is an apocalyptic number.

It is an amenable number.

1133320232013 is a deficient number, since it is larger than the sum of its proper divisors (377773410675).

1133320232013 is an equidigital number, since it uses as much as digits as its factorization.

1133320232013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 377773410674.

The product of its (nonzero) digits is 1944, while the sum is 24.

Adding to 1133320232013 its reverse (3102320233311), we get a palindrome (4235640465324).

The spelling of 1133320232013 in words is "one trillion, one hundred thirty-three billion, three hundred twenty million, two hundred thirty-two thousand, thirteen".

Divisors: 1 3 377773410671 1133320232013