Base | Representation |
---|---|
bin | 11001110001001100101011… |
… | …000011110000100001111111 |
3 | 112212021102202122101110012220 |
4 | 121301030223003300201333 |
5 | 104323312441224220210 |
6 | 1041012002511300423 |
7 | 32604653134141323 |
oct | 3161145303604177 |
9 | 485242678343186 |
10 | 113332024445055 |
11 | 3312492926a789 |
12 | 1086460981a713 |
13 | 4b3121954ab20 |
14 | 1ddb429203983 |
15 | d1805cd2ec70 |
hex | 67132b0f087f |
113332024445055 has 32 divisors (see below), whose sum is σ = 205557679971840. Its totient is φ = 52857689132160.
The previous prime is 113332024445047. The next prime is 113332024445113. The reversal of 113332024445055 is 550544420233311.
It is not a de Polignac number, because 113332024445055 - 23 = 113332024445047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113332024444998 and 113332024445016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15294466531 + ... + 15294473940.
It is an arithmetic number, because the mean of its divisors is an integer number (6423677499120).
Almost surely, 2113332024445055 is an apocalyptic number.
113332024445055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
113332024445055 is a deficient number, since it is larger than the sum of its proper divisors (92225655526785).
113332024445055 is a wasteful number, since it uses less digits than its factorization.
113332024445055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30588940511.
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 113332024445055 its reverse (550544420233311), we get a palindrome (663876444678366).
The spelling of 113332024445055 in words is "one hundred thirteen trillion, three hundred thirty-two billion, twenty-four million, four hundred forty-five thousand, fifty-five".
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