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1133323202993 is a prime number
BaseRepresentation
bin10000011111011111010…
…100111011000110110001
311000100022020112212121012
4100133133110323012301
5122032021214443433
62224350321240305
7144610543164602
oct20373724730661
94010266485535
101133323202993
113a7704447683
1216378b793095
1382b447b7977
143cbd300bda9
151e731212848
hex107df53b1b1

1133323202993 has 2 divisors, whose sum is σ = 1133323202994. Its totient is φ = 1133323202992.

The previous prime is 1133323202953. The next prime is 1133323203011. The reversal of 1133323202993 is 3992023233311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1101433458064 + 31889744929 = 1049492^2 + 178577^2 .

It is an emirp because it is prime and its reverse (3992023233311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1133323202993 - 214 = 1133323186609 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1133323202993.

It is not a weakly prime, because it can be changed into another prime (1133323202953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566661601496 + 566661601497.

It is an arithmetic number, because the mean of its divisors is an integer number (566661601497).

Almost surely, 21133323202993 is an apocalyptic number.

It is an amenable number.

1133323202993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133323202993 is an equidigital number, since it uses as much as digits as its factorization.

1133323202993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 157464, while the sum is 41.

The spelling of 1133323202993 in words is "one trillion, one hundred thirty-three billion, three hundred twenty-three million, two hundred two thousand, nine hundred ninety-three".