11333313300000 has 576 divisors, whose sum is σ = 37995781864320. Its totient is φ = 2956661760000.

The previous prime is 11333313299993. The next prime is 11333313300011. The reversal of 11333313300000 is 331333311.

It is a self number, because there is not a number n which added to its sum of digits gives 11333313300000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 7043699196 + ... + 7043700804.

It is an arithmetic number, because the mean of its divisors is an integer number (65964899070).

Almost surely, 2^{11333313300000} is an apocalyptic number.

11333313300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11333313300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18997890932160).

11333313300000 is an abundant number, since it is smaller than the sum of its proper divisors (26662468564320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11333313300000 is an equidigital number, since it uses as much as digits as its factorization.

11333313300000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2143 (or 2115 counting only the distinct ones).

The product of its (nonzero) digits is 729, while the sum is 21.

Adding to 11333313300000 its reverse (331333311), we get a palindrome (11333644633311).

The spelling of 11333313300000 in words is "eleven trillion, three hundred thirty-three billion, three hundred thirteen million, three hundred thousand".