113333144045101 has 4 divisors (see below), whose sum is σ = 113449862011104. Its totient is φ = 113216426079100.

The previous prime is 113333144045083. The next prime is 113333144045117. The reversal of 113333144045101 is 101540441333311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113333144045101 - 2²⁵ = 113333110490669 is a prime.

It is a super-2 number, since 2×113333144045101² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113333144040101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58358981545 + ... + 58358983486.

It is an arithmetic number, because the mean of its divisors is an integer number (28362465502776).

Almost surely, 2^{113333144045101} is an apocalyptic number.

It is an amenable number.

113333144045101 is a deficient number, since it is larger than the sum of its proper divisors (116717966003).

113333144045101 is an equidigital number, since it uses as much as digits as its factorization.

113333144045101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 116717966002.

The product of its (nonzero) digits is 25920, while the sum is 34.

Adding to 113333144045101 its reverse (101540441333311), we get a palindrome (214873585378412).

The spelling of 113333144045101 in words is "one hundred thirteen trillion, three hundred thirty-three billion, one hundred forty-four million, forty-five thousand, one hundred one".