Base | Representation |
---|---|
bin | 10101000111000011… |
… | …00010000011101101 |
3 | 1002020211210221012221 |
4 | 22203201202003231 |
5 | 141202323123203 |
6 | 5112334155341 |
7 | 550565255506 |
oct | 124341420355 |
9 | 32224727187 |
10 | 11333411053 |
11 | 4896462518 |
12 | 2243652b51 |
13 | 10b8022bb3 |
14 | 79729dbad |
15 | 464e9cabd |
hex | 2a38620ed |
11333411053 has 4 divisors (see below), whose sum is σ = 11369620348. Its totient is φ = 11297201760.
The previous prime is 11333410999. The next prime is 11333411071. The reversal of 11333411053 is 35011433311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 729972324 + 10603438729 = 27018^2 + 102973^2 .
It is a cyclic number.
It is not a de Polignac number, because 11333411053 - 221 = 11331313901 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11333411093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18104178 + ... + 18104803.
It is an arithmetic number, because the mean of its divisors is an integer number (2842405087).
Almost surely, 211333411053 is an apocalyptic number.
It is an amenable number.
11333411053 is a deficient number, since it is larger than the sum of its proper divisors (36209295).
11333411053 is an equidigital number, since it uses as much as digits as its factorization.
11333411053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36209294.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 11333411053 its reverse (35011433311), we get a palindrome (46344844364).
The spelling of 11333411053 in words is "eleven billion, three hundred thirty-three million, four hundred eleven thousand, fifty-three".
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