11334041433 has 24 divisors (see below), whose sum is σ = 19233527040. Its totient is φ = 6340721760.

The previous prime is 11334041431. The next prime is 11334041449. The reversal of 11334041433 is 33414043311.

11334041433 is a `hidden beast` number, since 113 + 3 + 404 + 143 + 3 = 666.

It is not a de Polignac number, because 11334041433 - 2¹ = 11334041431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11334041397 and 11334041406.

It is not an unprimeable number, because it can be changed into a prime (11334041431) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4401993 + ... + 4404566.

It is an arithmetic number, because the mean of its divisors is an integer number (801396960).

Almost surely, 2^11334041433 is an apocalyptic number.

11334041433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11334041433 is a deficient number, since it is larger than the sum of its proper divisors (7899485607).

11334041433 is a wasteful number, since it uses less digits than its factorization.

11334041433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8806589 (or 8806586 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 11334041433 its reverse (33414043311), we get a palindrome (44748084744).

The spelling of 11334041433 in words is "eleven billion, three hundred thirty-four million, forty-one thousand, four hundred thirty-three".