Base | Representation |
---|---|
bin | 110100110001110011… |
… | …1011110111000011011 |
3 | 101211112220001010100011 |
4 | 1221203213132320123 |
5 | 3324110123203222 |
6 | 124022355022351 |
7 | 11121452610535 |
oct | 1514347367033 |
9 | 354486033304 |
10 | 113340444187 |
11 | 440817a9293 |
12 | 19b7159a9b7 |
13 | a8c359ccb9 |
14 | 56b2aca855 |
15 | 2e354d8c77 |
hex | 1a639dee1b |
113340444187 has 2 divisors, whose sum is σ = 113340444188. Its totient is φ = 113340444186.
The previous prime is 113340444163. The next prime is 113340444221. The reversal of 113340444187 is 781444043311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113340444187 - 215 = 113340411419 is a prime.
It is not a weakly prime, because it can be changed into another prime (113340444787) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56670222093 + 56670222094.
It is an arithmetic number, because the mean of its divisors is an integer number (56670222094).
Almost surely, 2113340444187 is an apocalyptic number.
113340444187 is a deficient number, since it is larger than the sum of its proper divisors (1).
113340444187 is an equidigital number, since it uses as much as digits as its factorization.
113340444187 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129024, while the sum is 40.
Adding to 113340444187 its reverse (781444043311), we get a palindrome (894784487498).
The spelling of 113340444187 in words is "one hundred thirteen billion, three hundred forty million, four hundred forty-four thousand, one hundred eighty-seven".
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