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11334414311034 = 232697022561531
BaseRepresentation
bin1010010011101111111110…
…1111010001111001111010
31111010120002211011211202220
42210323333233101321322
52441200340030423114
640034542534504510
72246612232006213
oct244737757217172
944116084154686
1011334414311034
11367a997433481
121330828505136
13642aa501b8c9
142b28350c440a
15149c7a2a60a9
hexa4effbd1e7a

11334414311034 has 16 divisors (see below), whose sum is σ = 22753099363680. Its totient is φ = 3764092980080.

The previous prime is 11334414310981. The next prime is 11334414311137. The reversal of 11334414311034 is 43011341443311.

It is a junction number, because it is equal to n+sod(n) for n = 11334414310986 and 11334414311004.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3511279152 + ... + 3511282379.

It is an arithmetic number, because the mean of its divisors is an integer number (1422068710230).

Almost surely, 211334414311034 is an apocalyptic number.

11334414311034 is an abundant number, since it is smaller than the sum of its proper divisors (11418685052646).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11334414311034 is a wasteful number, since it uses less digits than its factorization.

11334414311034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7022561805.

The product of its (nonzero) digits is 20736, while the sum is 33.

Adding to 11334414311034 its reverse (43011341443311), we get a palindrome (54345755754345).

The spelling of 11334414311034 in words is "eleven trillion, three hundred thirty-four billion, four hundred fourteen million, three hundred eleven thousand, thirty-four".

Divisors: 1 2 3 6 269 538 807 1614 7022561531 14045123062 21067684593 42135369186 1889069051839 3778138103678 5667207155517 11334414311034