1133442031331 has 2 divisors, whose sum is σ = 1133442031332. Its totient is φ = 1133442031330.

The previous prime is 1133442031303. The next prime is 1133442031349. The reversal of 1133442031331 is 1331302443311.

It is a strong prime.

It is an emirp because it is prime and its reverse (1331302443311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1133442031331 - 2¹⁰ = 1133442030307 is a prime.

It is a super-2 number, since 2×1133442031331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1133442031294 and 1133442031303.

It is not a weakly prime, because it can be changed into another prime (1133442031361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566721015665 + 566721015666.

It is an arithmetic number, because the mean of its divisors is an integer number (566721015666).

Almost surely, 2^{1133442031331} is an apocalyptic number.

1133442031331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133442031331 is an equidigital number, since it uses as much as digits as its factorization.

1133442031331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 1133442031331 its reverse (1331302443311), we get a palindrome (2464744474642).

The spelling of 1133442031331 in words is "one trillion, one hundred thirty-three billion, four hundred forty-two million, thirty-one thousand, three hundred thirty-one".