1133442033133 has 4 divisors (see below), whose sum is σ = 1157557821120. Its totient is φ = 1109326245148.

The previous prime is 1133442033121. The next prime is 1133442033151. The reversal of 1133442033133 is 3313302443311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1133442033133 - 2²¹ = 1133439935981 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1133442033095 and 1133442033104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133442033733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12057893923 + ... + 12057894016.

It is an arithmetic number, because the mean of its divisors is an integer number (289389455280).

Almost surely, 2^{1133442033133} is an apocalyptic number.

It is an amenable number.

1133442033133 is a deficient number, since it is larger than the sum of its proper divisors (24115787987).

1133442033133 is an equidigital number, since it uses as much as digits as its factorization.

1133442033133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24115787986.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 1133442033133 its reverse (3313302443311), we get a palindrome (4446744476444).

The spelling of 1133442033133 in words is "one trillion, one hundred thirty-three billion, four hundred forty-two million, thirty-three thousand, one hundred thirty-three".