Base | Representation |
---|---|
bin | 110100110001111100… |
… | …0111001111101101001 |
3 | 101211120012122011121011 |
4 | 1221203320321331221 |
5 | 3324112310332221 |
6 | 124023040543521 |
7 | 11121536462515 |
oct | 1514370717551 |
9 | 354505564534 |
10 | 113345011561 |
11 | 44084338881 |
12 | 19b73021ba1 |
13 | a8c450bba2 |
14 | 56b3559145 |
15 | 2e35adc1e1 |
hex | 1a63e39f69 |
113345011561 has 2 divisors, whose sum is σ = 113345011562. Its totient is φ = 113345011560.
The previous prime is 113345011553. The next prime is 113345011573. The reversal of 113345011561 is 165110543311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74794045225 + 38550966336 = 273485^2 + 196344^2 .
It is a cyclic number.
It is not a de Polignac number, because 113345011561 - 23 = 113345011553 is a prime.
It is not a weakly prime, because it can be changed into another prime (113345011361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56672505780 + 56672505781.
It is an arithmetic number, because the mean of its divisors is an integer number (56672505781).
Almost surely, 2113345011561 is an apocalyptic number.
It is an amenable number.
113345011561 is a deficient number, since it is larger than the sum of its proper divisors (1).
113345011561 is an equidigital number, since it uses as much as digits as its factorization.
113345011561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 31.
Adding to 113345011561 its reverse (165110543311), we get a palindrome (278455554872).
The spelling of 113345011561 in words is "one hundred thirteen billion, three hundred forty-five million, eleven thousand, five hundred sixty-one".
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