Base | Representation |
---|---|
bin | 1010010011110010101001… |
… | …1111010000100100010000 |
3 | 1111010121221210202102100012 |
4 | 2210330222133100210100 |
5 | 2441203322133002121 |
6 | 40035142035214052 |
7 | 2246636061202121 |
oct | 244745237204420 |
9 | 44117853672305 |
10 | 11335131531536 |
11 | 368022527489a |
12 | 13309a8747328 |
13 | 642b8a7aa237 |
14 | 2b28a2462048 |
15 | 149cbd22ac5b |
hex | a4f2a7d0910 |
11335131531536 has 10 divisors (see below), whose sum is σ = 21961817342382. Its totient is φ = 5667565765760.
The previous prime is 11335131531511. The next prime is 11335131531547. The reversal of 11335131531536 is 63513513153311.
It can be written as a sum of positive squares in only one way, i.e., 11275868497936 + 59263033600 = 3357956^2 + 243440^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11335131531493 and 11335131531502.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 354222860345 + ... + 354222860376.
Almost surely, 211335131531536 is an apocalyptic number.
11335131531536 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
11335131531536 is a deficient number, since it is larger than the sum of its proper divisors (10626685810846).
11335131531536 is an equidigital number, since it uses as much as digits as its factorization.
11335131531536 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 708445720729 (or 708445720723 counting only the distinct ones).
The product of its digits is 182250, while the sum is 41.
Adding to 11335131531536 its reverse (63513513153311), we get a palindrome (74848644684847).
The spelling of 11335131531536 in words is "eleven trillion, three hundred thirty-five billion, one hundred thirty-one million, five hundred thirty-one thousand, five hundred thirty-six".
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